Second Largest In Array Java

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Second Largest In Array Java

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Find Second Smallest Number In An Array Java Video Tutorial

Web Oct 6 2023 nbsp 0183 32 Step 1 Initialize a map data Step 2 Store the elements of the array with their count in the map and map data structure always arrange the elements in their increasing order Step 3 If map size is greater than 1 then second largest exist else not exist ;Find the second largest element in the given array: public static void findSecondMax(){ int[] arr = {3, 2, 20, 4, 1, 9, 6, 3, 8}; int max = 0; int secondMax = 0; for(int i =0; i< arr.length; i++) { if(max < arr[i]) max = arr[i]; if((max > arr[i]) && (secondMax < arr[i])) secondMax = arr[i]; } System.out.println(secondMax); }

Second Largest In Array java YouTube

Second Largest In Array JavaProblem: The problem is to get the second largest array element. Observation: Second largest number is defined as the number that has the minimum difference when subtracted from the maximum element in the array. Solution: This is a two pass solution. First pass is to find the maximum number. Web Feb 16 2019 nbsp 0183 32 The given array is 50 6 60 70 80 90 9 150 2 35 Second largest number is 90 int max nums 0 secMax nums 0 for int x 0 x lt nums length x if nums x gt max secMax max max nums x Initialize max and scmax second max with 2

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