Quadratic Function Vertex Form

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Quadratic Function Vertex Form

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Graphing Quadratic Functions In Vertex Form YouTube

Y a x h 2 k is the vertex form equation Now expand the square and simplify You should get y a x 2 2hx h 2 k Multiply by the coefficient of a and get y ax 2 2ahx ah 2 k This is standard form of a quadratic equation with the normal a b and c in ax 2 bx c equaling a 2ah and ah 2 k respectively The vertex is (h, k) and the axis of symmetry is the vertical line x = h. When given a quadratic in general form: f(x) = ax2 + bx + c, more computation is required. After identifying parameters a and b , calculate h = – b 2a . Then find the corresponding y coordinate for that point on the graph: y = f(h) = k.

Changing A Quadratic Function Into Vertex Form YouTube

Quadratic Function Vertex FormLet us consider a quadratic equation in Vertex Form: #color (blue) (y=f (x)= (x-3)^2+8#, where. #color (green) (a=1; h=3; k=8#. Hence, #color (blue) ("Vertex "= (3, 8)#. To find the y-intercept, set #color (red) (x=0#. #y= (0-3)^2+8#. #y=9+8#. Finding the vertex of the quadratic by using the equation x b 2a and then substituting that answer for y in the orginal equation Then substitute the vertex into the vertex form equation y a x h 2 k a will stay the same h is x and k is y

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